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d^2=2880
We move all terms to the left:
d^2-(2880)=0
a = 1; b = 0; c = -2880;
Δ = b2-4ac
Δ = 02-4·1·(-2880)
Δ = 11520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{11520}=\sqrt{2304*5}=\sqrt{2304}*\sqrt{5}=48\sqrt{5}$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48\sqrt{5}}{2*1}=\frac{0-48\sqrt{5}}{2} =-\frac{48\sqrt{5}}{2} =-24\sqrt{5} $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48\sqrt{5}}{2*1}=\frac{0+48\sqrt{5}}{2} =\frac{48\sqrt{5}}{2} =24\sqrt{5} $
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